1/4(x+3)^2-9=-5

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Solution for 1/4(x+3)^2-9=-5 equation: 


x in (-oo:+oo)

(1/4)*(x+3)^2-9 = -5 // + 5

(1/4)*(x+3)^2-9+5 = 0

1/4*(x+3)^2-9+5 = 0

1/4*(x+3)^2-9+5 = 0

1/4*x^2+3/2*x-27/4+5 = 0

1/4*x^2+3/2*x-7/4 = 0

1/4*x^2+3/2*x-7/4 = 0

1/2*(1/2*x^2+3*x-7/2) = 0

1/2*x^2+3*x-7/2 = 0

DELTA = 3^2-(-7/2*1/2*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)-3)/(1/2*2) or x = (-16^(1/2)-3)/(1/2*2)

x = 1 or x = -7

1/2*(x+7)*(x-1) = 0

1/2*(x+7)*(x-1) = 0

( x+7 )

x+7 = 0 // - 7

x = -7

( x-1 )

x-1 = 0 // + 1

x = 1

x in { -7, 1 }

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